2

Suppose I want to sample 10 times from multiple normal distributions with the same covariance matrix (identity) but different means, which are stored as rows of the following matrix:

means = np.array([[1, 5, 2],
                  [6, 2, 7],
                  [1, 8, 2]])

How can I do that in the most efficient way possible (i.e. avoiding loops)

I tried like this:

scipy.stats.multivariate_normal(means, np.eye(2)).rvs(10)

and

np.random.multivariate_normal(means, np.eye(2))

But they throw an error saying mean should be 1D.

Slow Example

import scipy
np.r_[[scipy.stats.multivariate_normal(means[i, :], np.eye(3)).rvs() for i in range(len(means))]]
Euler_Salter
  • 3,271
  • 8
  • 33
  • 74

1 Answers1

1

Your covariance matrix indicate that the sample are independent. You can just sample them at once:

num_samples = 10
flat_means = means.ravel()

# build block covariance matrix
cov = np.eye(3)
block_cov = np.kron(np.eye(3), cov)

out = np.random.multivariate_normal(flat_means, cov=block_cov, size=num_samples)

out = out.reshape((-1,) + means.shape)
Quang Hoang
  • 146,074
  • 10
  • 56
  • 74