30

Couldn't find a solution.
I'm using react-hook-form and I want to disable the submit button when the forms are empty and enable as long as all forms have atleast something written in them.
How would I do that using react-hook-form?

Mr.Joony
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4 Answers4

46
const { 
    register, 
    handleSubmit, 
    formState: { isSubmitting, isDirty, isValid } // here
  } = useForm({ mode: "onChange" })


<button
  type="submit"
  disabled={!isDirty || !isValid} // here
>
  Comment
</button>
Joshua Galit
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    or you could get form state directly from `const { isDirty, isValid } = useFormState();` if used in nested components – Titenis Nov 25 '21 at 10:09
28

The best solution I found so far using formState and by setting the mode to onChange.

 const { register, handleSubmit, formState } = useForm({
    mode: "onChange"
  });

And on the submit button:

<button disabled={!formState.isValid}/>

Based on this issue: https://github.com/react-hook-form/react-hook-form/issues/77

onChange mode explanation from the documentation:

Validation will trigger on the change event with each input, and lead to multiple re-renders. Warning: this often comes with a significant impact on performance.

3

you can use formState => isDirty which means form is been modified.

https://react-hook-form.com/api#formState

here is a working example for formState below:

https://codesandbox.io/s/react-hook-form-v6-formstate-ht098?file=/src/index.jsx:423-432

<input disable={formState.isDirty} type="submit" />

Bill
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  • What if i want to disabled the submit button again after submit successful. I dont see that case mention the the doc. Thanks for the `react-hook-form` , it is a great lib. – vanduc1102 Aug 30 '23 at 15:54
0

Close but I think the logic is slightly off from the other comments. The key is to use the && operator. Credit to the example with the Formik library.

const { formState: { errors, isDirty, isValid } } = useForm()
///...
<button type="submit" disabled={!isDirty && !isValid}>
Continue
</button>
rottitime
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  • So when the form is dirty, yet invalid (false && true), it won't be disabled anymore? I don't think this is a suitable answer for most use cases. – Almog Cohen Oct 09 '22 at 11:16