Function returns tuple when it should not

Question

I am using python 2.7 and here is what I've got.

Method:

def get_phone(self):
    digits = filter(str.isdigit, str(self.phone))
    if re.match(r'(0|380)\d{9}', digits):
        operator = digits[-9:-7]
        digits = digits[-7:]
        return "+380 ({}) {}".format(opeself.rator, digits)
    return None

Now if I use this method like this:

dictionary = {
    'phone': User.get_phone()
}

the output is:

{'phone': '+380 (12) 1234567'}

But if I use it like so:

dictionary['phone'] = User.get_phone(),

The output becomes a tuple:

{'phone': ('+380 (12) 1234567',)}

What am I doing wrong?

You are not doing anything wrong, you are just creating a tuple... That trailing `,` makes the expression become a tuple of one element... Why did you add it? — Tomerikoo, Dec 17 '20 at 11:25

score 7 · Accepted Answer · answered Dec 17 '20 at 11:25

7

You added a comma here:

dictionary['phone'] = User.get_phone(),

That turns it into a tuple

answered Dec 17 '20 at 11:25

Johan

477
4
8

Function returns tuple when it should not

1 Answers1