Divide operation yields different result with the last decimal digit in Python, than that of a regular calc

Question

I am trying to perform a divide operation in python, (3000/365)*365 which prints 3000.0000000000005. Whereas in actual this should return 3000?

Can someone help me understand what am I missing here?

Does this answer your question? [Is floating point math broken?](https://stackoverflow.com/questions/588004/is-floating-point-math-broken) — user2390182, Dec 21 '20 at 07:20
As pointed out by others, what you're seeing is the result of floating point arithmetic. You might also be interested in exact decimal arithmetic. I think there are probably implementations of that for Python; a web search should find some resouces. — Robert Dodier, Dec 21 '20 at 19:51

score 0 · Accepted Answer · answered Dec 21 '20 at 07:19

0

Programming languages has floting point precesion errors. which cause sometime this kind of issues.

answered Dec 21 '20 at 07:19

Nitin Goyal

score 0 · Answer 2 · answered Dec 21 '20 at 07:26

As mentioned above, it is because of the precision when using floating points.

A solution would be to round the result:

(round(3000/365*365,2)

and if you don't want a float, you could use int

int((round(3000/365*365,2))

Not sure if there is another approach, but hope this helps.

2 Answers2