How do I correctly call a templated superclass' constructor?

Asked Dec 22 '20 at 08:11

Active Dec 22 '20 at 08:11

Viewed 31 times

I'm trying to implement a relatively basic Base class and Derived class, and getting stumped by an error I don't know how to resolve.

The code I've written is this:

template<bool Owning>
class Base {
protected:
    Base() = default;

    Base(int * ptr) {
        //Do something
    }
};

template<bool Owning>
class Derived : public Base<Owning> {
public:
    Derived() : Base(new int(5)) 
    {}
};

When I try to compile this code, I get the following error:

<source>: In constructor 'Derived<Owning>::Derived()':
<source>:14:17: error: class 'Derived<Owning>' does not have any field named 'Base'
   14 |     Derived() : Base(new int(5))
      |                 ^~~~
Compiler returned: 1

Clearly, there's something wrong with how I'm trying to call the Base class' constructor, but I don't know what the correct way to write this is. What should I be writing to get this code to behave properly?

asked Dec 22 '20 at 08:11

Xirema

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`Base(new int(5))` – john Dec 22 '20 at 08:14
OT: Why are you creating a pointer to a single `int` value? What problem is that supposed to solve? – Some programmer dude Dec 22 '20 at 08:15
@Someprogrammerdude It's called creating a [mcve]: I just needed to reduce the problem down to a version that showed the error I was facing. The actual code I'm working on is very different to this, but reliably produces the same error. – Xirema Dec 22 '20 at 08:16
@john If you post that as an answer I'll accept it. – Xirema Dec 22 '20 at 08:17
You could have made it [even simpler](https://godbolt.org/z/913dYs) ;) – Some programmer dude Dec 22 '20 at 08:19

How do I correctly call a templated superclass' constructor?

0 Answers0