How do I I get rid of the whitespaces before and after sys.argv when printing?

Question

Here is the code in my test.py file.

print ('The 2nd arg is: \'', sys.argv[1], '\'.')

Each time I run this command

python test.py hello

I get this

The 2nd arg is: ' hello '.

There are whitespaces before and after the string. How do I get rid of them?

I've tried strip() which doesn't work.

The comma in a print statement adds spaces. Use the "+" operator to concatenate without spaces. — Suraj Kothari, Dec 22 '20 at 14:23
Does this answer your question? [How to print variables without spaces between values](https://stackoverflow.com/questions/28669459/how-to-print-variables-without-spaces-between-values) — Tomerikoo, Dec 22 '20 at 14:30
From the [docs](https://docs.python.org/3/library/functions.html#print): *"`print(*objects, sep=' ', end='n', file=sys.stdout, flush=False)` - Print `objects` to the text stream `file`, __separated by `sep`__ and followed by `end`"* — Tomerikoo, Dec 22 '20 at 14:39

score 1 · Accepted Answer · answered Dec 22 '20 at 14:22

1

Issue is in your print function. You are getting extra white-spaces because of the , inside your print. This should fix the issue:

print ('The 2nd arg is: \'' + sys.argv[1] + '\'.')

answered Dec 22 '20 at 14:22

Jarvis

score 1 · Answer 2 · answered Dec 22 '20 at 14:26

1

you can use following formatting:

print ("The 2nd arg is:'{}'.".format(sys.argv[1]))

answered Dec 22 '20 at 14:26

tanujabhoyar

2 Answers2