Pass argument as member of a python dictionary

Question

I have 2 python files 1 where only dictionary is saved Example :

Dic.py

A={"1":{"a":1},    "2":{"b":2}}

And calldic.py

import dic

def todo(Value,Index):
    Data=dic.Value(Index)
    Print(Data)

As in the above code I am trying to pass argument as member of the dic.py file.

Can anyone please help me resolve this or correct me where I am wrong.

Thanks in advance

What exactly are you trying to achieve here? Also, python is case-sensitive. — Axe319, Dec 23 '20 at 11:33
I don't want to write code for each key in the dictionary I want to have it as dynamic , in the above code if I call todo method as todo(A,1) Value = A and Index = 1 it should fetch the data in it. — user3724559, Dec 23 '20 at 11:38
Please do not rate it down as I am posting this from my mobile and have restrictions example control key — user3724559, Dec 23 '20 at 11:40

Jarvis · Accepted Answer · 2020-12-23T11:55:03.480

1

If what I infer from your question is correct, this should work (assuming Value="A"):

variable_name = Value
attr = getattr(dic, variable_name)
data = attr.get(index)

or

data = attr[index]

Convert index to string before if you are passing index as an integer:

index = str(index)

Edit: As mentioned in the comment, you can use the dict attribute on modules/classes as well.

data = dic.__dict__[value][index]

edited Dec 23 '20 at 11:55

answered Dec 23 '20 at 11:46

Jarvis

Hi Jarvis thanks , but intend is I don't want to pass as A I want to make it dynamic like pass as argument of method todo like data=dic.Value[index] , it's a example I know it's wrong need help to correct it. – user3724559 Dec 23 '20 at 11:48
1

Alternatively, `data = dic.__dict__[value][index]`. – Axe319 Dec 23 '20 at 11:51
@user3724559 Please accept the answer to mark the issue resolved. – Jarvis Dec 23 '20 at 12:01
Yup have don't it apologize for delay – user3724559 Dec 23 '20 at 12:29

1 Answers1