meaning of this scanf { scanf("%[^\n]%*c", s);} in c

Question

int main()

{

char s[100];

char s1[] ={"Hello, World!"};

scanf("%[^\n]%*c", s); // The statement that we are interested in//

printf("%s",s1);

printf("\n");

printf("%s",s);

return 0;

}

Perhaps [a decent `scanf` reference](https://en.cppreference.com/w/c/io/fscanf) might be helpful? — Some programmer dude, Dec 23 '20 at 16:26

score 1 · Answer 1 · answered Dec 23 '20 at 16:29

There are already some post about this argument, such as this. By the way:
with %[^\n] you are taking input until a newline isn't encountered. With %*c you take the newline character and then discard it (this is useful when you are using fgets after scanf).

meaning of this scanf { scanf("%[^\n]%*c", s);} in c

1 Answers1