How to convert string number to int and avoid the string text before convert

Question

I would like to create the check condition string is string number or not so, how I can do in python

x = "String"
y = "12"

if x is string:
   print("this is string")
if y is string:
   print("this is not string")

`if x is string` If you want to check the _type_ of x, this is the wrong way to do it. Use `if type(x) is str` instead. — John Gordon, Dec 24 '20 at 02:04
Does this answer your question? [How to check if type of a variable is string?](https://stackoverflow.com/questions/4843173/how-to-check-if-type-of-a-variable-is-string) — Montgomery Watts, Dec 24 '20 at 02:05
Does this answer your question? [How can I check if a string represents an int, without using try/except?](https://stackoverflow.com/questions/1265665/how-can-i-check-if-a-string-represents-an-int-without-using-try-except) — DarrylG, Dec 24 '20 at 02:05

score 0 · Answer 1 · answered Dec 24 '20 at 02:06

0

You could try something like this:

array = ["String", "12"]

for item in array:
  try:
    int(item)
    print(f"{item} is not string")
  except:
    print(f"{item} is string")

answered Dec 24 '20 at 02:06

Graygood

score 0 · Answer 2 · answered Dec 24 '20 at 02:07

0

You can use .isdigit() method to fulfill this.

x = "String"
y = "12"

if not(x.isdigit()):
   print("this is string")
if y.isdigit():
   print("this is not string")

Output:

this is string
this is not string

answered Dec 24 '20 at 02:07

Harshana

2 Answers2