Check if user input is equal to an item's index in list

Question

I'm just wondering if it's possible to see if the users input equals an item's index within a list?

I am trying to do something like this:

data = ['hello', 'hi', 'hey']

user_choice = int(input("Enter 1,2 or 3: ")
user_answer = user_choice - 1
if user_answer in ....: # How would I finish this off line off?
    result = data[user_answer]
    print(result)

Does this answer your question? [If list index exists, do X](https://stackoverflow.com/questions/11786157/if-list-index-exists-do-x) — mkrieger1, Dec 25 '20 at 13:32

score -1 · Accepted Answer · answered Dec 25 '20 at 12:56

-1

data = ['hello','hi','hey']

user_choice = int(input("Enter 1,2 or 3: ")
user_answer = user_choice - 1
if user_answer in range(1,len(data)+1): #just give length of data
    result = data[user_answer]
    print(result)

answered Dec 25 '20 at 12:56

Nanthakumar J J

860
1
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This answer is wrong, it will fail if we input `1` and it's also inefficient. Instead use `if 0 <= user_answer < len(data)` as suggested in the comments by mkrieger. – Roy Cohen Dec 25 '20 at 13:39
@RoyCohen i did notice this to so i changed it but forgot to mention it in here. Thanks for noting this for others who check this question – SimpleJay_ Dec 25 '20 at 14:16

score -1 · Answer 2 · answered Dec 25 '20 at 12:57

I think you just need to put [1,2,3] or range(1,4) in your blank space.

data = ['hello','hi','hey']

user_choice = int(input("Enter 1,2 or 3: "))
user_answer = user_choice - 1
length = len(data)+1
if user_answer in range(1,length): #How would i finish this off line off?
    result = data[user_answer]
    print(result)

Results:

Enter 1,2 or 3: 2
hi

Check if user input is equal to an item's index in list

2 Answers2