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i want to build a program in Python designed for generating hazard numbers in lotto. For example from 1 to 45 , i want that every number between 1 and 45 ( 1 and 45 included) have the same chance to appear or not, like in real life. What is ( or what are) the appropriate random that can do that or closer to do that (approximation). EXEMPLE value= random.randint(1,46)
Does all the numbers between 1 and 45 have the same chance to appear or to not appear like in reel world ? Does chance in computer world is like chance in reel world, if no , how to make it closer? It is not about duplication. Thank you for helping

Moneym Brussel
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  • `from random import randint` then `randint(1, 45)` – James Dec 26 '20 at 14:18
  • Yes, all numbers should have the same chance. If that is not so, that would be a serious bug in the underlying random number generator. If you want to test it, simply repeatedly generate random numbers and count the occurrence of each. After a few million numbers, you should not be able to see statistically significant differences. – deceze Dec 26 '20 at 14:36

1 Answers1

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You want to sample k numbers, without replacement, from a discrete uniform distribution on the interval [1, 45].

Let's say you want to pick 6 numbers. Then write

import random

winners = random.sample(range(1, 46), k=6)

Then winners will be a list of six randomly chosen numbers.

Explanation:

  • range(1, 45) represents the interval [1, 45). In other words, it wouldn't include 45. So the second argument is 46.
  • sample chooses k numbers from that range of 45 without replacement. In other words, just like in the typical lottery, no number will be chosen twice — which you can't count on with other random module functions.
  • The distribution will be uniform by default; each number is equally likely to be chosen.
Noah
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