How can i count the numbers that given in bulk on python

Question

So I have these lines in python

l=list("09073146864462346440228042814284764104460294046232864221188427140442613004261248")

print("There is ",l.count("1"+"2"+"3"+"4"+"5"+"6"+"7"+"8"+"9"+"0")," Numbers in it")

I want it to count as separate the output would be like there is 50 numbers here.

what you want exactly? to count how many times occur '1','2' etc? or what — Devi Khositashvili, Dec 28 '20 at 16:25
Are you looking for [`len`](https://docs.python.org/3/library/functions.html#len)? — Sayandip Dutta, Dec 28 '20 at 16:27
len() is the answer thanks a lot i dont know how i forgot it, havent been coding for a while — MAKO, Dec 28 '20 at 16:31
Does this answer your question? [How can I count the occurrences of a list item?](https://stackoverflow.com/questions/2600191/how-can-i-count-the-occurrences-of-a-list-item) — Sayandip Dutta, Dec 28 '20 at 16:32

score 0 · Answer 1 · answered Dec 28 '20 at 16:30

0

So im told it was len() function so it is solved thanks* the code should be

l=list("09073146864462346440228042814284764104460294046232864221188427140442613004261248")

print("There is ",len(l)," Numbers in it")

answered Dec 28 '20 at 16:30

MAKO

13
2

How can i count the numbers that given in bulk on python

1 Answers1