Error: Variable-sized object may not be initialized. But why?

Question

enter code hereint quantity = [array count];
int i;
for (i=0; i<quantity; i++) 
{
    NSString *imageName = [NSString stringWithFormat:@"Car_%@.jpg",  [[array objectAtIndex:i] objectForKey:@"CarName"]]   ];
    UIImage *img[i] = [UIImage imageNamed:imageName];
    UIImageView *imgView[i] = [[UIImageView alloc] initWithImage:img[i]];
    imgView[i].frame = CGRectMake(i*kWidth, 0, kWidth, kHeight);
    [scrollView addSubview:imgView[i]];
    [imgView[i] release];
}`enter code here`

Jim · Answer 1 · 2011-07-01T16:45:43.340

UIImage *img[i] = [UIImage imageNamed:imageName];

This declares a C-style array of size i and attempts to initialise it with an instance of UIImage. That doesn't make sense. What are you trying to do? Where is the rest of your code?

Edit:

Okay, I think I see what you are doing. Just get rid of all the places you have [i]. Inside the loop, you are only dealing with one item at a time, and even if you weren't, that's not how you use arrays.

score 1 · Accepted Answer · answered Jul 01 '11 at 16:45

You may want to try this:

int i;
for (i=0; i<quantity; i++) 
{
    NSString *imageName = [NSString stringWithFormat:@"Car_%@.jpg",  [[array objectAtIndex:i] objectForKey:@"CarName"]]   ];
    UIImage *img = [UIImage imageNamed:imageName];
    UIImageView *imgView = [[UIImageView alloc] initWithImage:img];
    imgView.frame = CGRectMake(i*kWidth, 0, kWidth, kHeight);
    [scrollView addSubview:imgView];
    [imgView release];
}

You don't need to use img[i] in order to populate a scrollview with UIImageView.

Error: Variable-sized object may not be initialized. But why?

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