How to click the specific button with Selenium and Python?

Question

Iam trying to find and click on this button. But i always face with "Message: Unable to locate element:"

I try this options, but its doesnt help me:

First: driver.find_element_by_xpath('//button[contains(text(), "CLAIM NOW!")]').click()

Second: driver.find_element_by_xpath('//button[@onclick="getClaim()"]').click()

Third: driver.find_element_by_css_selector('a.btn').click()

Fourth: driver.find_element_by_class_name('btn btn-lg btn-primary').click()

Firth: driver.find_element_by_id('roll_button_container').click()

Also iam using time.sleep() so its not problem with time

Flow of actions: After I click on the "Claim Now!" a new tab will open, but in the previous one (which I am on now) - I will get points. And I need to automate this on the project

My almost full code ( cant show you everything as company policy):

from selenium  import webdriver
import time

driver = webdriver.Firefox (executable_path = "/Users/USER1/Downloads/AUTOMATION/geckodriver")

driver.get("https://LINK.net/")
time.sleep(3)
driver.find_element_by_xpath('/html/body/header/nav/div/div/ul/li[5]/a').click()
time.sleep(3)
element = driver.find_element_by_xpath('/html/body/div[3]/div/div/form/div[1]/input').send_keys("login")
time.sleep(3)
el2 = driver.find_element_by_xpath('/html/body/div[3]/div/div/form/div[2]/input').send_keys("password")
time.sleep(3)
driver.find_element_by_css_selector('#loginForm > div:nth-child(3) > button:nth-child(1)').click()
time.sleep(3)
driver.find_element_by_xpath('//*[@id="test_button"]').click()
time.sleep(3)
#driver.find_element_by_xpath('//button[contains(text(), "CLAIM NOW!")]').click()
#driver.find_element_by_xpath('//button[@onclick="getClaim()"]').click()
#driver.find_element_by_class_name('btn btn-lg btn-primary').click()
#driver.find_element_by_id('roll_button_container').click()
driver.find_element_by_css_selector('a.btn').click()
time.sleep(3)
driver.quit()

while True:
  time.sleep(60 * 5)

Does anyone can help me to click on button correctly? Thanks a lot.

Button

I add screenshot, so anyone can look at. As you can see - its empty, but i dont know what you mean, sorry — valeracripts, Dec 31 '20 at 10:32
An URL would be more helpful, that screenshot contains no useful data. The js function `getClaim`, that you want to click might contain a page, that you can load without simulate the button click. — nagyl, Dec 31 '20 at 10:34
Okay, show us your code, and do not blur the URL out! We can't help you this way. — nagyl, Dec 31 '20 at 10:43
I can see only one image in the question, please update the page — valeracripts, Dec 31 '20 at 11:33
Same picture 3 times. You can check in the edit log. 1, https://i.stack.imgur.com/UXOoY.png 2, https://i.stack.imgur.com/kTaWD.png 3, https://i.stack.imgur.com/PIxC7.png — nagyl, Dec 31 '20 at 11:34
Ok, as you cant click on the link inside a question - i will share with you https://i.stack.imgur.com/ezMtL.png — valeracripts, Dec 31 '20 at 13:37
XPaths need to be corrected //a[contains(text(),'CLAIM N0W!')] or //a[@onclick="getClaim()"] — Janesh Kodikara, Dec 31 '20 at 16:15

score 0 · Answer 1 · answered Dec 31 '20 at 11:45

Okay, looks like that the page redirects you to a page that is full of fake ads. By clicking the link, a random ad would pop up each time. Alternatively you can run getClaim with selenium as js.

You may claim your reward by simulating the button press - running the function that the button would run - only running javascript with selenium.

cmd = "getClaim()"
driver.execute_script(cmd)

I hope, as you would say, a "poor indian" could help you.

How to click the specific button with Selenium and Python?

1 Answers1