I compile C using the C99 version, and I want to try and output the timezone of the given time.
The IDE I use gives GMT+0 as the timezone, but I want to somehow output it with struct tm
.
So I followed the instructions from this answer and made this program:
#include <stdio.h>
#include <time.h>
int main()
{
time_t present = time(NULL);
struct tm now = *localtime(&present);
now.tm_mon += 1;
now.tm_year += 1900;
struct tm t = {0};
localtime_r(&present, &t);
printf("%i/%i/%i %i:%i:%i from %s\n", now.tm_mon, now.tm_mday, now.tm_year, now.tm_hour, now.tm_min, now.tm_sec, t.tm_zone);
}
And it seems like I got 2 errors here:
implicit declaration of function 'localtime_r' is invalid in C99
no member named 'tm_zone' in 'struct tm'
So I checked the IDE Manual, and find that localtime_r
actually exists, and is part of the <time.h>
library.
So now I'm wondering if the IDE's confused or something. I don't know how to fix it either.
This might get closed as it might "need debugging details", but read more.
Because of this whole situation, how can I get the timezone (maybe even the offset) in C99 and get it to be outputted with printf()
?