Convert 1/2/2021 to 2021-2-1

Question

I have a string that comes in the format name = "1/2/2021", how can I convert this string to the format newName = "2021-2-1"

original =  name
day = original[0]
month = original[2]
year = original[4:8]
combination = year + "-" + month + "-" + day

I have tried using this but brings wrong values when date or month changes to more than 2 characters

Import datetime and convert it. Also Stack Overflow has so many examples of this already https://stackabuse.com/converting-strings-to-datetime-in-python/ — Joe Ferndz, Jan 03 '21 at 02:33

score 0 · Accepted Answer · answered Jan 03 '21 at 02:34

0

without using date/time functions:

n1 = name.split("/")
print(f"{n1[2]}-{n1[1]}-{n1[0]}")

answered Jan 03 '21 at 02:34

ktp

126
8

score 0 · Answer 2 · answered Jan 03 '21 at 02:43

0

new = original.split("/")[2]+"-"+original.split("/")[1]+"-"+original.split("/")[0]

answered Jan 03 '21 at 02:43

Synthase

5,849
2
12
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Add some explanation to your code please. It's understandable, but it will be better to add some description – ppwater Jan 03 '21 at 05:24

score 0 · Answer 3 · answered Jan 03 '21 at 03:06

Passing string and delimiter as "/" also works without datetime.

def splitStrings(st, dl):
    word = ""
    st += dl
    l = len(st)
    substr_list = []
    for i in range(l):
        if (st[i] != dl):
            word += st[i]
        else:
            if (len(word) != 0):
                substr_list.append(word)
            word = ""
    return substr_list


def getCutDate(self, string):
    out = (splitStrings(string, '/'))
    day = out[0]
    month = out[1]
    year = out[2][0:4]
    result = year + "-" + month + "-" + day
    return result

Convert 1/2/2021 to 2021-2-1

3 Answers3