I am not sure if that is the right logic to go there. Subtraction of two Long values, in this case, time in milliseconds, is not what you should be doing. There is an option to find a difference between two dates in seconds, minutes, etc. Use this to show your time left.
Check this code, which you can simplify because you don't have to use everything in here:
DateTimeUtils obj = new DateTimeUtils();
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd/M/yyyy hh:mm:ss");
try {
Date date1 = simpleDateFormat.parse("10/10/2013 11:30:10");
Date date2 = simpleDateFormat.parse("13/10/2013 20:35:55");
obj.printDifference(date1, date2);
} catch (ParseException e) {
e.printStackTrace();
}
//1 minute = 60 seconds
//1 hour = 60 x 60 = 3600
//1 day = 3600 x 24 = 86400
public void printDifference(Date startDate, Date endDate) {
//milliseconds
long different = endDate.getTime() - startDate.getTime();
System.out.println("startDate : " + startDate);
System.out.println("endDate : "+ endDate);
System.out.println("different : " + different);
long secondsInMilli = 1000;
long minutesInMilli = secondsInMilli * 60;
long hoursInMilli = minutesInMilli * 60;
long daysInMilli = hoursInMilli * 24;
long elapsedDays = different / daysInMilli;
different = different % daysInMilli;
long elapsedHours = different / hoursInMilli;
different = different % hoursInMilli;
long elapsedMinutes = different / minutesInMilli;
different = different % minutesInMilli;
long elapsedSeconds = different / secondsInMilli;
System.out.printf(
"%d days, %d hours, %d minutes, %d seconds%n",
elapsedDays, elapsedHours, elapsedMinutes, elapsedSeconds);
}
Output:
startDate : Thu Oct 10 11:30:10 SGT 2013
endDate : Sun Oct 13 20:35:55 SGT 2013
different : 291945000
3 days, 9 hours, 5 minutes, 45 seconds
To get your dates you can simply use
Date endDate = simpleDateFormat.format(new Date(calendarEnd.getTimeInMillis()));
Date currentDate = simpleDateFormat.format(new Date(Calendar.getInstance().getTimeInMillis()));