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iOS 14's UIMenu seems to be able to be presented from any UIBarButtonItem or UIButton / UIControl, but I how would I present it from a generic UIView?

Joel Fischer
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1 Answers1

1

Add the interaction:

let interaction = UIContextMenuInteraction(delegate: self)
menuView.addInteraction(interaction)

Add UIContextMenuInteractionDelegate to your controller:

extension YourViewController: UIContextMenuInteractionDelegate {
               
      func contextMenuInteraction(_ interaction: UIContextMenuInteraction, configurationForMenuAtLocation location: CGPoint) -> UIContextMenuConfiguration? {
        return UIContextMenuConfiguration(identifier: nil, previewProvider: nil) { suggestedActions in
            
            // Create an action for sharing
            let share = UIAction(title: "Share", image: UIImage(systemName: "square.and.arrow.up")) { action in
                // Show system share sheet
            }
    
            // Create an action for renaming
            let rename = UIAction(title: "Rename", image: UIImage(systemName: "square.and.pencil")) { action in
                // Perform renaming
            }
    
            // Here we specify the "destructive" attribute to show that it’s destructive in nature
            let delete = UIAction(title: "Delete", image: UIImage(systemName: "trash"), attributes: .destructive) { action in
                // Perform delete
            }
    
            // Create and return a UIMenu with all of the actions as children
            return UIMenu(title: "", children: [share, rename, delete])
        }
    }
}

Now, long-press on the view and see your menu :)

More here: https://kylebashour.com/posts/context-menu-guide

TonyMkenu
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    I apologize if it wasn't fully clear, I'm looking to present the menu from a generic `UIView` _without_ a long press. – Joel Fischer Jan 07 '21 at 19:35