Extract 15 digit string from text using regex (re.findall) in python

Question

My input is--

Text = "My name is Alex , house no - 254456845 with mobile no. +91-11-22558845 and my account no. is - AB12569BF214558."

Now I want to use regex (re.findall) on my input text and get the expected output.

Expected Output= ( it contains both digits and alphabet and is always of length = 15 )

[ "AB12569BF214558" ]

please help

The duplicate link given is not, IMHO, enough because it doesn't include the exact regex logic/approach which is needed here. — Tim Biegeleisen, Jan 05 '21 at 06:40

Matt Miguel · Answer 1 · 2021-01-05T10:29:29.880

0

import re
results = re.findall('\\b[A-Z0-9]{15}\\b','''My name is Alex , house no - 254456845 with mobile no. +91-11-22558845 and my account no. is - AB12569BF214558.''')

edited Jan 05 '21 at 10:29

answered Jan 05 '21 at 05:34

Matt Miguel

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this solution gives me my expected output in this case, but when i use this code in other cases then i gives me all the strings that have length 15 or more, i just want that string length should be strictly 15 only and not other string with length more than 15 should be given in output. – Lokesh Choraria Jan 05 '21 at 07:44
The {15} means exactly 15 characters. Fifteen or more would be {15,} – Matt Miguel Jan 05 '21 at 07:54
Oh I think I understand what you mean. The result is only 15 characters, but it is part of a longer string. Adding the '\b' at the start and end per Tim B's answer takes care of that. – Matt Miguel Jan 05 '21 at 07:55
@MukulKant Please don't mark code only answers like this. Otherwise you will get banned from reviewing. – 10 Rep Jan 05 '21 at 17:15

score 0 · Accepted Answer · answered Jan 05 '21 at 05:36

You should be using the following regex pattern:

\b[A-Z0-9]{15}\b

This will ensure that you match a string of uppercase/numbers which is exactly 15 characters in length. Sample script:

Text = "My name is Alex , house no - 254456845 with mobile no. +91-11-22558845 and my account no. is - AB12569BF214558."
matches = re.findall(r'\b[A-Z0-9]{15}\b', Text)
print(matches)

This prints:

['AB12569BF214558']

Extract 15 digit string from text using regex (re.findall) in python

2 Answers2