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I have text a 1 b 2 c 3.

How can I make a dictionary in which letters would be keys, and numbers values?

I know how I would make it if it was in in multiple rows, I do not know how to do it when it is in one row.

mkrieger1
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Aleksa Malezic
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2 Answers2

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Convert the string to list. And then list to dictionary.

str1 = "a 1 b 2 c 3"
lst = str1.split(" ")
dct = {lst[i]: lst[i + 1] for i in range(0, len(lst), 2)}
mkrieger1
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Maleehak
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-1
text = "a 1 b 2 c 3"
myDictionary = {}
for i in range(0,len(text),4):
    myDictionary[text[i]]=text[i+2]
print(myDictionary)
#output : {'c': '3', 'a': '1', 'b': '2'}
omkar
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  • This code will not work with the string given in the question. – mkrieger1 Jan 09 '21 at 12:02
  • if you have spaces you can use this, if you have two digit value then you should check for that , if you do not specify actually what you need then it become difficult to answer. – omkar Jan 09 '21 at 12:07
  • Now it works with the exact string given in the question, but what if there are numbers greater than 9 involved, for example `text = "a 10 b 12 c 32"`? – mkrieger1 Jan 09 '21 at 12:07
  • just split the string and convert into a list so it will be easier for you to make dictionary myList = list(text.split()) – omkar Jan 09 '21 at 12:09
  • so list will become [a,12,b,45,...] like that so using indexing you can make dictionary – omkar Jan 09 '21 at 12:10