Why converting individual characters of a string to integer using "Convert.ToInt32()" method gives weird result in C#?

Asked Jan 10 '21 at 11:00

Active Jan 10 '21 at 11:00

Viewed 33 times

Here is sample code:

    using System;

    namespace MessingWithFourDigitNumbers
    {
        class FourDigitManipulation
        {
            static void Main()
            {
                string numString = "1234";
                for(int i = 0; i < numString.Length; i++)
                {
                    Console.WriteLine(Convert.ToInt32(numString[i]));
                }
        }
    }
}

Result was:Weird Result

Instead of:

asked Jan 10 '21 at 11:00

Ankit Minz

1

You aren't converting strings to integers, you're casting `Char` values to their numeric equivalents. `String[i]` returns a *Char*, not a string – Panagiotis Kanavos Jan 10 '21 at 11:01
Use `Convert.ToInt32(numString[i].ToString())`. You may also use `int.Parse()` (or int.TryParse()` if the input might not always be an integer) instead of `Convert.ToInt32()`. – 41686d6564 stands w. Palestine Jan 10 '21 at 11:02
Because of ASCII values. ASCII values of '1', '2', '3' are 49, 50, 51 43 respectively – Prasad Telkikar Jan 10 '21 at 11:03
Use Console.WriteLine(numString[i] - ‘0’) – user1672994 Jan 10 '21 at 11:03

Why converting individual characters of a string to integer using "Convert.ToInt32()" method gives weird result in C#?

0 Answers0