Not able to replace the file contents with sed command

Asked Jan 11 '21 at 11:35

Active Jan 11 '21 at 11:35

Viewed 17 times

I am trying to replace the pattern of the file from below command inside the shell script -

 "sed -i 's/start.datetime.*/start.datetime=$param_date 00:00:00/g'" conf.txt

But it gives below error -

./Test.sh: line 22: sed -i 's/start.datetime.*/start.datetime=2021-01-11 00:00:00/g': No such file or directory

However the very next line which is below gives required output -

echo `grep start.datetime conf.txt`
start.datetime=2020-12-01 00:00:00

I am not able to figure out why the sed not able to locate the file and replace the pattern.

asked Jan 11 '21 at 11:35

RAHUL SONI

2

Why do you have double quotes around the sed command? – oguz ismail Jan 11 '21 at 11:37
Variable param_date is not visible otherwise to the sed. – RAHUL SONI Jan 11 '21 at 11:41
1

You need to put them around the sed script, not the whole command. Like `sed -i "s/..."` – oguz ismail Jan 11 '21 at 11:42
1

Use double quotes for parameter expansion or single quotes otherwise. Don't use both. – Raman Sailopal Jan 11 '21 at 11:44

0 Answers0