Python pass array into function and use it in json return

Question

I have the following python code:

import requests

def requestAPI(url):
  return requests.get(url=url).json()

UselessFact = RequestApi("https://uselessfacts.jsph.pl/random.json?language=en")['text']

I wanted to put a try/except on the requestAPI function so it does'nt break the code. I thought about this:

import requests

def requestAPI(url, keys):
  return requests.get(url=url).json() #Here is the struggle with passing the "keys" parameter into the return

UselessFact = RequestApi("https://uselessfacts.jsph.pl/random.json?language=en", ['text'])

I could do something like:

import requests

def requestAPI(url):
  try:
    return requests.get(url=url).json() 

  except:
    return False

UselessFact = RequestApi("https://uselessfacts.jsph.pl/random.json?language=en")['text'] if (condition here) else False

But i think there's a better way of doing this.

Jarvis · Accepted Answer · 2021-01-14T02:20:31.113

2

You can achieve it without a try-except via dict.get():

def requestAPI(url, key):
    return requests.get(url=url).json().get(key, None)

This will return the value for key key if it exists in the JSON otherwise it will return None. If you want it to return False, do .get(key, False).

edited Jan 14 '21 at 02:20

answered Jan 14 '21 at 02:18

Jarvis

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I knew it could be better! Thank you! – William Brochensque junior Jan 14 '21 at 02:20
How could i do it with multiple keys? (An array of them) – William Brochensque junior Jan 14 '21 at 12:10
1

You can check [this](https://stackoverflow.com/a/58000060/4806357) answer, or the other ones. – Jarvis Jan 14 '21 at 12:12

Python pass array into function and use it in json return

1 Answers1