C# JsonSerializer.Serialize>(numbers) will output a json with a list of 0's

Question

using System;
using System.Collections.Generic;
using System.Text.Json;
using System.IO;
using System.Numerics;

List<BigInteger> numbers = new List<BigInteger>();
numbers.Add(4);
numbers.Add(3);
File.WriteAllText("example.json", JsonSerializer.Serialize<List<BigInteger>>(numbers);
numbers = JsonSerializer.Deserialize<List<BigInteger>>(File.ReadAllText("example.json"));
foreach(BigInteger i in numbers)
{
      Console.WriteLine(i);
}

output: 0 0

expected: 4 3

It seems like Jsonserializer isn't serializing a list of BigInteger correctly. what am I doing wrong here?

This already got closed as "Needs Debugging Details" for some reason, but in reality it looks to be a duplicate of [Serialising BigInteger using System.Text.Json](https://stackoverflow.com/q/64788895/3744182). — dbc, Apr 06 '21 at 18:54

JKC · Accepted Answer · 2021-01-16T06:32:47.323

1

Did you mean knownPrimes insted of numbers ?

var knownPrimes= JsonSerializer.Deserialize<List<BigInteger>>

(File.ReadAllText("example.json"));

Update You can use this for working reference or testing

List<BigInteger> numbers = new List<BigInteger>();
            numbers.Add(4);
            numbers.Add(3);
            File.WriteAllText("example.json", JsonConvert.SerializeObject(numbers));
            var number = JsonConvert.DeserializeObject<List<BigInteger>>(File.ReadAllText("example.json"));
            foreach (BigInteger i in numbers)
            {
                Console.WriteLine(i);
            }

edited Jan 16 '21 at 06:32

answered Jan 15 '21 at 02:40

JKC

79
6

no I mean numbers instead of knownprimes. – Travis Rivera Jan 16 '21 at 05:31
I updated my answer I use JsonConvert.SerializeObject and JsonConvert.DeserializeObject instead, Please mark it as answer if it helps. – JKC Jan 16 '21 at 06:33

C# JsonSerializer.Serialize>(numbers) will output a json with a list of 0's

1 Answers1