Why am i getting a 0 result in this program when i enter 3?

Question

If i enter a value lets say "3" i get a result of 0. Please explain why and if there is a way please show me. Should I use float?

#include <stdio.h>
int getResult (int nVal)
int c , f;
int nExp;
double dSum;
f = 1;
dSum = 0;

nExp = nVal;
for (c = 1; c <= nVal; c++)
{
    f = f * c;
    dSum += f / nExp;
    nExp = nExp * nVal;
}

return  dSum;
int main ()
{

int nVal, nCompute;
double dSum;
printf("Enter Number to be Computed");
scanf("%d",&nVal);

nCompute = getResult (nVal);

printf("%d", nCompute);

return 0;   
}

I've rolled back your edit because it completely changed the nature of the question after you already had an answer. If you have a different question, please create a new post. — Caleb, Jan 15 '21 at 19:42

score 2 · Answer 1 · answered Jan 15 '21 at 19:19

2

f and nExp are ints, so you're dividing them using integer division, keeping only the "whole" part of the result, to the left of the decimal point, which is zero. Instead, you define one or both of them as doubles, so you'd be performing floating-point division.

answered Jan 15 '21 at 19:19

Mureinik

297,002
52
306
350

i changed them to double but im still getting a result of 0 – user14997606 Jan 15 '21 at 19:29
change every `int` to `float` including the ones in `main()` function and the argument of `getResult()` function. – itsDV7 Jan 15 '21 at 19:31
1

And don't forget to change `printf`'s format specifier accordingly. – Ruud Helderman Jan 15 '21 at 19:36
ooohh alright i solved the question thanks – user14997606 Jan 15 '21 at 19:39

Why am i getting a 0 result in this program when i enter 3?

1 Answers1