If character in string put escape character "\" in front of the found character

Question

I am requesting an API which sometimes gives a string that contain "*" characters. I have to post the output on discord, where ** makes the text bold. I want to see if a string contains any * and if so put a markdown \ escape character in front of the *.

How can I accomplish this?

[`str.replace()`](https://docs.python.org/3/library/stdtypes.html#str.replace) — Olvin Roght, Jan 15 '21 at 19:48
Does this answer your question? [how to replace back slash character with empty string in python](https://stackoverflow.com/questions/12618030/how-to-replace-back-slash-character-with-empty-string-in-python) — Joe Ferndz, Jan 15 '21 at 20:13
@RandomDavis can you make it an answer so I can accept it as the solution. And thank you. — aquatic7, Jan 15 '21 at 20:13

score 1 · Accepted Answer · answered Jan 15 '21 at 20:02

1

As @Random Davis rightly pointed out in the comments, you can use str.replace("*","\*")and it will replace all the * occurrence.

answered Jan 15 '21 at 20:02

Adivardhan Maheshwari

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it would be best to also add an example so OP can see clearly how the solution works – Joe Ferndz Jan 15 '21 at 20:09
@JoeFerndz, I agree, that would normally be appreciated. But I understood it and it's working now :) – aquatic7 Jan 15 '21 at 20:16

If character in string put escape character "\" in front of the found character

1 Answers1