Regex for password must contain at least eight characters, at least one number and both lower and uppercase letters

Question

I am using

/^(?=.\d)(?=.[a-z])(?=.*[A-Z])[0-9a-zA-Z]{8,}$/

But the problem is when I add any special character like !/@/#... etc, this regex doesn't valid.

for example:

"Customer12" is valid. "@Customer12" is not valid

I need a regex where "Customer12" and "@Customer12" would be valid. regex would not be affected by special character (~!@#$%^&*()_+).

How can I create a regex where password must contain at least eight characters, at least one number and both lower and uppercase letters?

I havent tested @Amaarrockz solution however, going regex makes sense for compactness. I will post an answer that doesn't use regex for comparison — GetSet, Jan 17 '21 at 04:50

score 1 · Answer 1 · answered Jan 17 '21 at 04:54

Regex is superior in terms of succinctness. But here is a non-regex solution which becomes ever more so readable for the non-regex linguist:

function validatePasswordWithoutRegex(pw) {
    // Regex for password must contain at least eight characters, at least one number and both lower and uppercase letters
    
    
    pw = pw.trim();
    
    // must contain at least eight characters
    if (pw.length < 8) return false;
    
    let alpha = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    let numeric = "0123456789";
    
    
    // at least one number 
    let okay = false;
    for (var i = 0; i < numeric.length; i++) {
        if ( pw.indexOf( numeric.charAt( i ) ) != -1) {
            okay = true;
            break;
        }
    }
    if ( !okay ) return false;
    
    // and both lower and uppercase letters (upper)
    okay = false;
    for (var i = 0; i < alpha.length; i++) {
        if ( pw.indexOf( alpha.charAt( i ) ) != -1) {
            okay = true;
            break;
        }
    }
    if ( !okay ) return false;
    
    // and both lower and uppercase letters (lower)
    okay = false;
    for (var i = 0; i < alpha.length; i++) {
        if ( pw.indexOf( alpha.charAt( i ).toLowerCase() ) != -1) {
            okay = true;
            break;
        }
    }
    if ( !okay ) return false;
    
    
    return true; // passed requirements

}

console.log( validatePasswordWithoutRegex( "ABC" ) );
    console.log( validatePasswordWithoutRegex( "hello world" ) );
    console.log( validatePasswordWithoutRegex( "he12World" ) );
    console.log( validatePasswordWithoutRegex( "12345678" ) );
    console.log( validatePasswordWithoutRegex( "123a5678" ) );
    console.log( validatePasswordWithoutRegex( "123a56B8" ) );
    console.log( validatePasswordWithoutRegex( "Hello12rld" ) );

Amaarockz · Answer 2 · 2021-01-17T04:43:23.837

0

Regex expression for Atleast eight characters, at least one letter and one number:

/^(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{8,}$/

It you want atleast eight characters, at least one letter and one number and one special character then you can use the below expression.

/"^(?=.*[A-Za-z])(?=.*\d)(?=.*[@$!%*#?&])[A-Za-z\d@$!%*#?&]{8,}$/

edited Jan 17 '21 at 04:43

answered Jan 17 '21 at 04:38

Amaarockz

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Regex for password must contain at least eight characters, at least one number and both lower and uppercase letters

2 Answers2