public class questions {
public static void main(String[] args)
{
Scanner userInput = new Scanner (System.in);
System.out.println("Enter two numbers: ");
int num1 = userInput.nextInt() ;
int num2 = userInput.nextInt() ;
(num1==num2) ? System.out.println("Same"): System.out.println("Not same"); // i am getting an error in that line
}
}
how can i compare these two numbers from user inputs with the conditional operator ?
Java separates some elements of your program into statements and expressions. A statement is an instruction to do something, and an expression is code that produces some value. You can write an expression and ignore the value (Math.sin(0);), called an expression statement, but a statement on its own has no value and can't be made into an expression.
The conditional/ternary operator ?: works only on expressions; that is, it's not a general flow-control tool like if but can only be used to select between two alternate values. Since System.out.println returns void (no value), it can only be called as a statement and thus can't be used as a ternary.
You can always use if to select between entirely different statements (usually and preferably block statements); if you want to use the conditional operator with System.out.println you must use it to select an expression to be passed to it as its argument:
System.out.println(condition ? "true" : "false"); // an expression of type String
You should assign a string response to a ternary expression with similar logic, and then print that message:
int num1 = userInput.nextInt();
int num2 = userInput.nextInt();
String msg = num1 == num2 ? "Same" : "Not same";
System.out.println(msg);
Try something like this instead:
System.out.println((num1 == num2) ? "Same" : "Not same");
