Do not exit if the file is not found python3

Question

Hi I have a list of filenames When reading a file, it comes out with an error

Traceback (most recent call last):
  File "test.py", line 229, in <module>
    f = open(i, 'r')
FileNotFoundError: [Errno 2] No such file or directory: 'directory_home.json'

How can I skip the error and complete the rest of the files?

code

file = ["directory_home.json", "directory_ever.json", "home.json", "home.json"]
for i in file: 
    f = open(i, 'r')
    data = json.load(f) 
    for i in data['name']:
        print(i)

Check if [it exists](https://stackoverflow.com/questions/82831/how-do-i-check-whether-a-file-exists-without-exceptions) first. — Yevhen Kuzmovych, Jan 17 '21 at 20:45

Matt Cottrill · Accepted Answer · 2021-01-17T22:51:44.147

3

Something like this. Note that 'pass' goes to next iteration. 'Continue' would repeat iteration (in this case useless). 'Break' would end iteration.

file = ["directory_home.json", "directory_ever.json", "home.json", "home.json"]
for i in file:
    try:
        f = open(i, 'r')
        data = json.load(f) 
        for i in data['name']:
            print(i)
        f.colse()
    except FileNotFoundError:
        print("File does not exist")
        pass

edited Jan 17 '21 at 22:51

answered Jan 17 '21 at 20:47

Matt Cottrill

152
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15

2

PEP 8: E722 do not use bare 'except' – Lydia van Dyke Jan 17 '21 at 20:48
1

And close the file, please – Yevhen Kuzmovych Jan 17 '21 at 20:49
`continue` does not repeat iteration, it skips all the code remaining in the loop and jumps to the next iteration. In this particular case, a `continue` instead of the `pass` would work exactly the same because it is the last statement in the loop so there's nothing to skip. – Czaporka Jan 24 '21 at 10:59

score 3 · Answer 2 · answered Jan 17 '21 at 20:48

Two options.

Option 1: os.path.isfile

import os
file = ["directory_home.json", "directory_ever.json", "home.json", "home.json"]
for i in file:
    if os.path.isfile(file):
        f = open(i)
        data = json.load(f) 
        for i in data['name']:
            print(i)
    else:
        continue # or whatever you want to do.

Option 2: Exception handling

file = ["directory_home.json", "directory_ever.json", "home.json", "home.json"]
for i in file: 
    try:
        f = open(i, 'r')
    except FileNotFoundError:
        continue # or whatever
    data = json.load(f) 
    for i in data['name']:
        print(i)

score 0 · Answer 3 · answered Jan 17 '21 at 20:49

You should pur your code in a try-except statement, like this

try:
     file = ["directory_home.json", "directory_ever.json", "home.json", "home.json"]
     for i in file: 
     f = open(i, 'r')
     data = json.load(f) 
     for i in data['name']:
           print(i)
except FileNotFoundError as e:
     # log exception and do whatever you want
     pass

In this way, if your code raises an exception because the file si not present, you are able ti handle It.
Please remember that in the code above, just the exception due to a not existing file si catch. This means that if another exception occurs the code will raise a traceback

Do not exit if the file is not found python3

3 Answers3