Python program to convert Hexadecimal to IEEE-754 Floating Point with Single precision

Question

I'm writing a Python program to decode Base64(Raw Data) output from my sensors to find it's latitude and longitude.

After checking the documents (attached below) that came with the sensor to decode the values, I'm still unsure on how to achieve it. I found a partial solution to convert it below but not sure how to achieve the final output.

So for example, if the Hexa value is B4 39 F5 42, my latitude output should be 1.3768.

import binascii
import struct


data = 'F9 7B 9C 45'
fdata = struct.unpack('<f', binascii.unhexlify(data.replace(' ', '')))[0]
print(fdata)

output:

5007.49658203125

Does this answer your question? [Convert hex to float](https://stackoverflow.com/questions/1592158/convert-hex-to-float) — PacketLoss, Jan 19 '21 at 04:35
Hi @PacketLoss, I tried the first two answers it doesn't seem to solve. — Daniel, Jan 19 '21 at 05:20

score 2 · Accepted Answer · answered Jan 19 '21 at 05:14

2

You are almost there. You should now convert the floating point number to degrees as specified in the docs you attached:

deg = fdata // 100 + (fdata % 100) / 60

The result would be 50.124943033854166 for 'F9 7B 9C 45' and 1.3768783569335938 for 'B4 39 F5 42'.

answered Jan 19 '21 at 05:14

Selcuk

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Thanks @Selcuk. Got the desired output. – Daniel Jan 19 '21 at 06:17

Python program to convert Hexadecimal to IEEE-754 Floating Point with Single precision

1 Answers1