Right now, I achieve it by
if (obj instanceof Uint8Array || obj instanceof Uint16Array || obj instanceof Uint32Array ......
Its a very long line. I know that testing instanceof against the parent class of an object yields true so is there a parent class among those typed arrays? I tried TypedArray but according to chrome it doesn't exist.
Anyone know if there is a base class between the typed arrays? Or some other method?
The TypedArray prototype does exist but is not exposed directly. You can get it using Object.getPrototypeOf from any of its typed arry subclasses, like this:
>> const TypedArray = Object.getPrototypeOf(Uint8Array)
>> console.log((new Uint32Array()) instanceof TypedArray)
true
So with the above const TypedArray in scope, your check simply becomes:
if (obj instanceof TypedArray) { ... }
I know this is not a very good solution but I think you can achieve the same kind of behavior using a hacky way. Actually, I don't like this kind of solution. I used Uint8Array.__proto__, I have no idea why the prototype of Uint arrays doesn't exist in chrome.
const uint8Array = new Uint8Array();
const uint16Array = new Uint16Array();
const uint32Array = new Uint32Array();
console.log(uint8Array instanceof Uint8Array.__proto__); //true
console.log(uint16Array instanceof Uint8Array.__proto__); //true
console.log(uint32Array instanceof Uint8Array.__proto__); //true
Edit:
const typedArrays = [new Uint8Array(), new Uint16Array(), new Uint32Array()];
const result = typedArrays.every(elem => elem instanceof Uint8Array.__proto__);
console.log(result);
So, you can check any typed array using Uint8Array.__proto__.
Edit 2:
const isTypedArray = (arg) => {
return arg instanceof Uint8Array.__proto__;
};
console.log(isTypedArray(uint8Array));// true
console.log(isTypedArray(uint16Array));// true
console.log(isTypedArray(uint32Array));// true
How about shorten it by checking if it not a normal array like this :
if (!(obj instanceof Array)) {
// Do stuff with typed array
}
