How to pass arguments to bash command

Question

I try to pass this result in the third command -d argument, But i failed.

$ cat asnlookups_domains_ip.txt | awk '{print $1}' | amass intel -whois -d 
flag needs an argument: -d

(OT: [Useless use of `cat`](https://en.wikipedia.org/wiki/Cat_(Unix)#Useless_use_of_cat)) — Biffen, Jan 21 '21 at 10:43
Please [don't post images of text.](https://meta.stackoverflow.com/questions/303812/discourage-screenshots-of-code-and-or-errors) — tripleee, Jan 21 '21 at 10:52

apaolillo · Accepted Answer · 2021-01-21T15:05:33.143

0

You could try xargs:

cat asnlookups_domains_ip.txt | awk '{print $1}' | xargs -n1 amass intel -whois -d

It passes the standard input as arguments after your command.

edited Jan 21 '21 at 15:05

answered Jan 21 '21 at 10:40

apaolillo

Hi `xargs` output like `example.com evilzone.com` . I need to pass one by one domain name on -d argument. – Jan 21 '21 at 11:37
2

@Shuvasaha Try `xargs -n1 …`. – Biffen Jan 21 '21 at 14:55
@Biffen It is working as I need it. Thank you very much – Jan 21 '21 at 15:03
1

I edited the answer to include the "-n1" – apaolillo Jan 21 '21 at 15:05

1 Answers1