So that the result of the check is always true

Question

You need to always be true in the console)

Without gaps, without rounding to the integer, without changing the comparison operator and the general calculation logic, as well as the loop condition )

P.S. This is an interview task for junior level ...

for (let i = 0; i <= 10; i++) {
  console.log(i + ':' + ((i * 0.1) == (i / 10)));
}
// needed to always true in console.log

What CAN be changed then? Also: [Is floating point math broken?](https://stackoverflow.com/questions/588004) — adiga, Jan 21 '21 at 13:34
@Weedoze they probably want to get the same value when a number multiplied by 0.1 and divided by 10. But, not sure what can be changed in the code. Because of [how floating points work](https://stackoverflow.com/questions/588004), it is not possible with the current code — adiga, Jan 21 '21 at 13:37
If you have any question about the given code, please add it to your question by editing it — Nico Haase, Feb 01 '21 at 07:42

score 1 · Answer 1 · answered Jan 21 '21 at 13:41

I would just create a function to compare the difference to a threshold e.g. 0.001.

/**
 * Determines if two floating value are equal within a threshold
 * @param {Number} a - First floating value
 * @param {Number} b - Second floating value
 * @param {Number} [t=0.001] - Threshold of difference
 * @return {boolean} Whether the difference is less than the threshold
 */
const equalsFloat = (a, b, t = 0.001) => Math.abs(a - b) < t;

for (let i = 0; i <= 10; i++) {
  console.log(`${i}: ${equalsFloat(i * 0.1, i / 10)}`);
}

.as-console-wrapper { top: 0; max-height: 100% !important; }

So that the result of the check is always true

1 Answers1