int main()
{
if(sizeof(int)>-1)
printf("true");
else
printf("False");
return 0;
}
This Programm While Running Prints Out "False". Why Does This Happen? Even though it's Size was 4?
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Satyabrata Kar
- 19
- 4
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1type promotion duplicate – IrAM Jan 22 '21 at 06:12
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1`sizeof`returns an `unsigned`value and `-1`is `signed` – Mike Jan 22 '21 at 06:13
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even though i put a positive integer there then also it prints out FALSE – Satyabrata Kar Jan 22 '21 at 06:16
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1better show the code – IrAM Jan 22 '21 at 06:19
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oops sry this is working now . after putting a positive integer it is printing True – Satyabrata Kar Jan 22 '21 at 06:22
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Duplicate: [Implicit type promotion rules](https://stackoverflow.com/questions/46073295/implicit-type-promotion-rules). I won't close vote since I'm partial. What you should look for specifically, is "the usual arithmetic conversions". – Lundin Jan 22 '21 at 09:52
1 Answers
2
the result of sizeof() is unsigned value while the right side of the comparison is signed. The compiler will convert the right side into unsigned (a very big number) first, then compare.
Brad Pitt
- 398
- 3
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why the negative number will have a very big value and how it will have that value? i mean any rule or process? – Satyabrata Kar Jan 22 '21 at 14:42
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@SatyabrataKar This link will help you https://stackoverflow.com/a/50632/5644356 – Brad Pitt Jan 23 '21 at 03:58