Python printing spaces, fizz buzz

Question

I wrote the code for a fizz buzz game, where it prints fizz for multiples of 3 and buzz for multiples of 5. Then fizz buzz for both everything works but the output. Its supposed to print 1: 2: 3: fizz

and so on but mine prints an extra space

1 : 2 : 3 : fizz

I provided the code below thanks for any help

def fizzbuzz(n):
  for num in range(1,n+1):
    if num % 3 == 0 and num % 5 == 0:
      print(num,': FizzBuzz')
    elif num % 3 == 0:
      print(num,": Fizz")
    elif num % 5 ==0:
      print(num,": Buzz")
    else:
      print(num,":")




fizzbuzz(n=21)

`print` adds a whitespace between the arguments it receives. Use string interpolation — DeepSpace, Jan 22 '21 at 22:10
What @DeepSpace said. https://pyformat.info/ provides a good documentation. — Ankur, Jan 22 '21 at 22:11
Lots of answers here: https://stackoverflow.com/questions/15286401/print-multiple-arguments-in-python — jarmod, Jan 22 '21 at 22:11
Read the docs on [print](https://docs.python.org/3/library/functions.html#print), you can change the ``sep=' '`` argument — Mike Scotty, Jan 22 '21 at 22:11

score 0 · Answer 1 · answered Jan 22 '21 at 22:13

Probably f strings could work, but it only works for python 3.6 and above of it.

def fizzbuzz(n):
  for num in range(1,n+1):
    if num % 3 == 0 and num % 5 == 0:
      print(f'{num} FizzBuzz')
    elif num % 3 == 0:
      print(f'{num} Fizz')
    elif num % 5 ==0:
      print(f'{num} Buzz')
    else:
      print(f'{num}:')
      
fizzbuzz(n=21)

Python printing spaces, fizz buzz

1 Answers1