University exercise, i'm trying to understand what this means

Question

const int N = 5;

struct array_str {
    int array[N];
    unsigned int size;
};

int main(int argc, const char * argv[]) {
    // insert code here...
    std::cout << "Hello, World!\n";
    return 0;
}

void readArray(array_str& v){
    
    for (<#initialization#>; <#condition#>; <#increment#>) {
        <#statements#>
    }
    
}

What does "array_str& v" means in the parenthesis? I'm not passing the struct bcs I would do that in this way "struct array_str name", v is a variable but why would you write it like that?

This is not the right platform to ask questions about basic language syntax. It's a reference. — Thomas Sablik, Jan 26 '21 at 16:54
[Looks like you should get a good C++ book](https://stackoverflow.com/questions/388242/the-definitive-c-book-guide-and-list) — PaulMcKenzie, Jan 26 '21 at 16:55
And by "it's a reference" we mean to say `array_str& v` means that `v` is a reference to struct `array_str`. It is not needed to specify struct there. — Dialecticus, Jan 26 '21 at 16:56

score 1 · Accepted Answer · answered Jan 26 '21 at 16:55

1

is the parameter of the type array_str passed as reference under the name v when you call the function readArray

answered Jan 26 '21 at 16:55

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University exercise, i'm trying to understand what this means

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