How do I make this regular expression not match anything after forward slash /

Question

I have this regular expression:

/^www\.example\.(com|co(\.(in|uk))?|net|us|me)\/?(.*)?[^\/]$/g

It matches:

www.example.com/example1/something

But doesn't match

www.example.com/example1/something/

But the problem is that, it matches: I do not want it to match:

www.example.com/example1/something/otherstuff

I just want it to stop when a slash is enountered after "something". If there is no slash after "something", it should continue matching any character, except line breaks.

I am a new learner for regex. So, I get confused easily with those characters

Try `^www\.example\.(com|co(?:\.(?:in|uk))?|net|us|me)(?:\/([^\/]+))?(?:\/([^\/]+))?$` — Wiktor Stribiżew, Jan 28 '21 at 09:56
Ok. I was confused by the string "something", I thought you wanted to forbid the third slash only when appearing after a specific string. — logi-kal, Jan 28 '21 at 10:00
Then use `^www\.example\.(com|co(?:\.(?:in|uk))?|net|us|me)\/([^\/]+)\/([^\/]+)$` — Wiktor Stribiżew, Jan 28 '21 at 10:05

anubhava · Answer 1 · 2021-01-28T10:05:02.670

2

You may use this regex:

^www\.example\.(?:com|co(?:\.(?:in|uk))?|net|us|me)(?:\/[^\/]+){2}$

RegEx Demo

This will match following URL:

www.example.co.uk/example1/something

edited Jan 28 '21 at 10:05

answered Jan 28 '21 at 09:59

anubhava

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Can you make it so that it doesn't match 1,2,3,4,,6 – Example person Jan 28 '21 at 10:00
Please suggest complete URL that don't want to match – anubhava Jan 28 '21 at 10:01
I do not want to match: `www.example.com` `www.example.com/` `www.example.com/example1` `www.example.com/example1/` `www.example.com/example1/something/` – Example person Jan 28 '21 at 10:03
So you just want to match `www.example.co.uk/example1/something` ? – anubhava Jan 28 '21 at 10:04
1

Thanks that worked out. I can't accept answer because there is cooldown – Example person Jan 28 '21 at 10:05
jfyi If you want to capture part after domain name use: `^www\.example\.(?:com|co(?:\.(?:in|uk))?|net|us|me)((?:\/[^\/]+){2})$` – anubhava Jan 28 '21 at 10:09
I am already confused about these. .... Just stop for a moment – Example person Jan 28 '21 at 10:09

Wiktor Stribiżew · Accepted Answer · 2021-01-28T10:08:48.327

1

You can use

^www\.example\.(?:com|co(?:\.(?:in|uk))?|net|us|me)\/([^\/]+)\/([^\/]+)$

See the regex demo

The (.*)? part in your pattern matches any zero or more chars, so it won't stop even after encountering two slashes. The \/([^\/]+)\/([^\/]+) part in the new pattern will match two parts after slash, and capture each part into a separate group (in case you need to access those values).

Details:

^ - start of string
www\.example\. - www.example. string
(?:com|co(?:\.(?:in|uk))?|net|us|me) - com, co.in, co.uk, co, net, us, me strings
\/ - a / char
([^\/]+) - Group 1: one or more chars other than /
\/ - a / char
([^\/]+) - Group 2: one or more chars other than /
$ - end of string.

edited Jan 28 '21 at 10:08

answered Jan 28 '21 at 09:58

Wiktor Stribiżew

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Your answer or that person's answer. I am confused – Example person Jan 28 '21 at 10:07
I can't decide yet – Example person Jan 28 '21 at 10:07
@Chi.C.J.RajeevaLochana If you need to access the capturing group values (those after slashes), my solution is what you need. If that's not important, select any you like. – Wiktor Stribiżew Jan 28 '21 at 10:07
Yours seems more clearer to me. because I am a newbie – Example person Jan 28 '21 at 10:08
`?:` vs `?` in regex? – Example person Jan 28 '21 at 10:11
1

@Chi.C.J.RajeevaLochana `(?:...)` is a [non-capturing group](https://stackoverflow.com/questions/3512471/what-is-a-non-capturing-group-in-regular-expressions), it is used to group patterns in order to either use alternation `|` operator or quantify them. The value matched is not stored as a submatch in the match object. `?` is just a quantifier that matches 1 or 0 occurrences of the pattern it modifies. – Wiktor Stribiżew Jan 28 '21 at 10:13

How do I make this regular expression not match anything after forward slash /

2 Answers2