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My old friend the 3d array called Pop, I want to remove columns (d2), across all of d3 when the value in the end of d1 == 1, so I have this code:

Pop[end, :, 1] .!=1

I thought adding @view in front of this would write the changes back to Pop, outwith producing an additional copy in memory. This code works fine

@view(Pop[ :, Pop[end, :, 1] .!=1, :])

but it does not alter the original 3d array called Pop. I could do

Pop = @view(Pop[ :, Pop[end, :, 1] .!=1, :])

but I believe this will create another copy in memory which I'm trying to avoid. What simple syntax have I missed? Thx. J

Jim Maas
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1 Answers1

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@view does not modify the size of the original array, it provides a "view" into it, (e.g., omitting some columns in your case). I don't think there is anything wrong with

Pop = view(Pop, :, Pop[end, :, 1] .≠ 1, :)

since now Pop is a view into your old, full Pop, but it behaves like an array, so you can modify its entries, e.g., you could then do things like

julia> using Random # using a fixed seed for reproducibility

julia> Random.seed!(0) ;

julia> Pop = rand(1:5, (2,4,2)) # original Pop
2×4×2 Array{Int64,3}:
[:, :, 1] =
 4  3  5  5
 1  1  3  5

[:, :, 2] =
 2  2  3  1
 2  5  1  1

julia> Pop[end,:,1] .≠ 1 # columns to keep
4-element BitArray{1}:
 0
 0
 1
 1

julia> Pop = view(Pop, :, Pop[end, :, 1] .≠ 1, :) # make it a view
2×2×2 view(::Array{Int64,3}, :, [3, 4], :) with eltype Int64:
[:, :, 1] =
 5  5
 3  5

[:, :, 2] =
 3  1
 1  1

julia> Pop[end,:,1] .= 1 ; # use your new view to manipulate data

julia> Pop # view of the modified Pop
2×2×2 view(::Array{Int64,3}, :, [3, 4], :) with eltype Int64:
[:, :, 1] =
 5  5
 1  1

[:, :, 2] =
 3  1
 1  1

julia> Pop.parent # original full Pop (now Pop.parent) has been modified
2×4×2 Array{Int64,3}:
[:, :, 1] =
 4  3  5  5
 1  1  1  1

[:, :, 2] =
 2  2  3  1
 2  5  1  1
Benoit Pasquier
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