Regex with quotes

Question

I'm working on a project and I have a problem with regex, I want to test some html attributes and it works, but when I have a quotes inside this does not work.

When I add the quote I have this result.

So I hope you can help me. (I check in javascript)

/([-\$@\w\d\i]+)="([-. =\:;()'\$@\w\d\i]*)"/gim

Well, it is not that difficult to deduce the pattern that should work, but you could explain the pattern requirements verbally. Something like `/([^\s=]+)="([^"\\]*(?:\\[\w\W][^"\\]*)*)"/g` should work. — Wiktor Stribiżew, Jan 28 '21 at 18:13
You're using Javascript. Turn the string into a DOM Object and XPath it... — MonkeyZeus, Jan 28 '21 at 18:13
If you have a web browser, the ability to create a `.html` file, and open it in the web browser then you absolutely have access to the DOM. — MonkeyZeus, Jan 28 '21 at 18:22
In fact, if you do that then open the console in Chrome and use `$x()` to execute XPaths directly without the need for writing JS code. — MonkeyZeus, Jan 28 '21 at 18:23
My application is not used in a browser, I use Node to launch my script. — Antharuu, Jan 28 '21 at 18:24
Please try `/([^\s=]+)="([^"\\]*(?:\\[\w\W][^"\\]*)*)"/g`. Does it work? — Wiktor Stribiżew, Jan 28 '21 at 18:40

score 1 · Accepted Answer · answered Jan 28 '21 at 18:46

You can use

/([^\s=]+)="([^"\\]*(?:\\[\w\W][^"\\]*)*)"/g

See the regex demo. Details:

([^\s=]+) - Group 1:
=" - a =" text
([^"\\]*(?:\\[\w\W][^"\\]*)*) - Group 2: any zero or more chars other than " and \ and then zero or more repetitions of any escape sequence followed with any zero or more chars other than " and \
" - a " char.

See the JavaScript demo:

const regex = /([^\s=]+)="([^"\\]*(?:\\[\w\W][^"\\]*)*)"/g;
const str = 'title="Bonjour - \\"(le monde))\\"" style="color: red;" charset="utf-8" src="monImage.png" alt=""\ntes-t6=""';
let m, results={};
while ((m = regex.exec(str))) {
  results[m[1]]=m[2];
}
console.log(results);

Regex with quotes

1 Answers1