How to locate the span element with Xpath Selenium and Python

Question

My HTML format is below:

***button class="btn authorize unlocked"

span>Authenticate</span

button***

So when I use "browser.find_element_by_xpath('//span[@class = "btn authorize unlocked"]')" to locate this button, it can not find that.

Message: no such element: Unable to locate element: {"method":"xpath","selector":"//span[@class = "btn authorize unlocked"]"}

So what should I change?

score 1 · Accepted Answer · answered Jan 29 '21 at 22:38

To locate the element you can use either of the following Locator Strategies:

Using css_selector:

element = driver.find_element(By.CSS_SELECTOR, "button.btn.authorize.unlocked > span")

Using xpath:

element = driver.find_element(By.XPATH, "//button[@class='btn authorize unlocked']/span[text()='Authenticate']")

Ideally, to locate the element you need to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:

Using CSS_SELECTOR:

element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "button.btn.authorize.unlocked > span")))

Using XPATH:

element = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//button[@class='btn authorize unlocked']/span[text()='Authenticate']")))

Note : You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

How to locate the span element with Xpath Selenium and Python

1 Answers1