creating multiple instances of a class in Python

Question

so let's say there is a class A

and I can create instances of class A as follow

inst1 = A()

inst2 = A()

inst3 = A()
...

Can I do this job more neatly?

I have to create the instances as many as a certain number that is given by a server (the number can vary every time).

I'm expecting to do something like

for NUM in range(2):
    inst + NUM = A()

then the instances I want to get as a result would be three instances (inst0, inst1, inst2) that are class A.

Thank you in advance

Does this answer your question? [How do you create different variable names while in a loop?](https://stackoverflow.com/questions/6181935/how-do-you-create-different-variable-names-while-in-a-loop) — M-Chen-3, Jan 30 '21 at 16:41
Don't dynamically create variables use a *container* like a list or a dict — juanpa.arrivillaga, Jan 30 '21 at 16:46

Leonardo Scotti · Accepted Answer · 2021-01-30T16:52:45.773

you can't create single variable if you don't assign them a specified name, for creating unknow amount of variables use lists (inndexed) or dictionarys (named):

Lists

with for loops:

instances = []

for x in range('number of instances'):

    instances.append(A())

with list comprehension (recommended):

instances = [A() for x in range('number of instances')]

Dictionarys

with for loops:

instances = {}

for x in range('number of instances'):

    instances['inst' + str(x)] = A()

with dict comprehension (recommended):

instances = {'inst' + str(x): A() for x in range('number of instances')}

score 3 · Answer 2 · answered Jan 30 '21 at 16:48

3

use a dictionary or list to create your variable

dictionary

d={}
for x in range(1, 10):
    d[f"inst{x}"] = A()

list

inst=[]
for i in range(10):
    inst.append(A())

answered Jan 30 '21 at 16:48

Papop Lekhapanyaporn

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creating multiple instances of a class in Python

2 Answers2