Keeping the values separately in the dictionary with for loop in Python

Question

I've reviewed many questions in StackOverflow that may be related to my question Q1, Q2, Q3, Q4 None of them are related to my question. Apart from these, I examined almost 20 questions here.

I created a sample code block to explain my problem simply. My aim is to add data to a dictionary in for loop.

When I run the code block below, the output is as follows.

dictionary = defaultdict(int)

for uid in range(10):
    for i in range(5):
        distance = 2*i
        dictionary[uid] = distance

Output

My aim is to keep the key value in each loop and add on it.

Expected Output:

{0: {0,2,4,6,8,}, 1:{0,2,4,6,8,}, 2:{0,2,4,6,8} , ...

My Solution

from collections import defaultdict

dictionary = defaultdict(int)
    
    for uid in range(10):
        for i in range(5):
            distance = 2*i
            dictionary[uid].append(distance)

My solution approach is also not working there is a problem

You just need to declare your defaultdict type as `list` instead of `int` — crissal, Jan 31 '21 at 14:19
do you need it to be a `list` or a `set`? the expected output shows `set` — gold_cy, Jan 31 '21 at 14:20

score 0 · Accepted Answer · answered Jan 31 '21 at 15:36

Try this:

from collections import defaultdict

dictionary = defaultdict(set)
for uid in range(10):
    for i in range(5):
        distance = 2*i
        dictionary[uid].add(distance)

Output (dictionary):

> defaultdict(set,
            {0: {0, 2, 4, 6, 8},
             1: {0, 2, 4, 6, 8},
             2: {0, 2, 4, 6, 8},
             3: {0, 2, 4, 6, 8},
             4: {0, 2, 4, 6, 8},
             5: {0, 2, 4, 6, 8},
             6: {0, 2, 4, 6, 8},
             7: {0, 2, 4, 6, 8},
             8: {0, 2, 4, 6, 8},
             9: {0, 2, 4, 6, 8}})

Keeping the values separately in the dictionary with for loop in Python

1 Answers1