is there a way to compare two strings without converting the Case?

Question

I've searched enough but didn't find the solution, I want to get True for comparing these strings without converting them to lower case or uppercase. also if there is a solution if I use them as arrays, is accepted and ok for me.

const  string1 = "My dear friend"
var    string2 = "my dEar frienD"

`string1.localeCompare(string2)`, if it is true it will return 1 other wise -1 for false. — Tashi Dendup, Feb 01 '21 at 08:25

score 2 · Accepted Answer · answered Feb 01 '21 at 08:26

2

You can use localCompare() which supports case insensitive comparisons.

const  string1 = "My dear friend"
var    string2 = "my dEar frienD"

console.log(string1.localeCompare(string2, undefined, { sensitivity: 'base' }) === 0)

answered Feb 01 '21 at 08:26

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is there a way to compare two strings without converting the Case?

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