Convert first 2 elements of a dictionary array to tuple

Question

How can I convert the first 2 elements of each array into tuple index?

Current

 {0: [1, 1, 0],
 1: [1, 2, 357],
 2: [1, 3, 167],
 3: [1, 4, 155]}

Desired Outcome

 {(1, 1): 0,
  (1, 2): 357,
  (1, 3): 167,
  (1, 4): 155}

Did you try anything? Did your code fail? – David Feb 01 '21 at 08:26 — David, Feb 01 '21 at 08:26
What should happen if they produce the same tuple? – Sayse Feb 01 '21 at 08:30 — Sayse, Feb 01 '21 at 08:30

score 2 · Answer 1 · answered Feb 01 '21 at 08:28

You could do it using dictionary comprehension in the following way:

d = {0: [1, 1, 0],1: [1, 2, 357],2: [1, 3, 167],3: [1, 4, 155]}
res = {(v[0],v[1]):v[2] for v in d.values()}

Where res is:

{(1, 1): 0, (1, 2): 357, (1, 3): 167, (1, 4): 155}

This solution will be problematic if you have duplicate tuples. You should address it in some way.

score 0 · Answer 2 · answered Feb 01 '21 at 08:40

Loop through the dictionary's values and use tuple unpacking to extract three elements. Pack the first two elements inside a tuple as a key. Assign the last element as a value of the new tuple.

dictionary = {
    0:[1,1,0],
    1:[1,2,357],
    2:[1,3,167],
    3:[1,4,155],
}
result = {(j,k):i for j,k,i in dictionary.values()}

or

result = {}
for j,k,i in dictionary.values():
    result[(j,k)] = i

Convert first 2 elements of a dictionary array to tuple

2 Answers2