How to implement alternately waiting for two elements in Pytest? try except doesn't match

Question

After submitting the request, there are two possible options:

1. The request cannot be executed and a notification about the rejection of the request will appear

2. The request can be executed and a button will appear to confirm the request. Now the implementation is as follows, try waits for a rejection notification, and if not executed by timeout, then except looks for a request confirmation button. The disadvantage of this approach is that it takes 10 minutes to process the request. And if the button for confirming the request appears at 5 seconds, then all the same there will be a 10 minute wait for the notification about the rejection of the request, we lose time. I saw on the Internet the approach of waiting for two elements through the lambda functions of Python, but I could not figure out what and how. Can someone help? or suggest alternative solutions to the problem

    def reject_request(self):
    id_pending = self._get_element_text(Main.pending_locates.pending_id)
   
    try:
        self._wait_for_visible(Main.pending_locates.reject_window)
        id_result = self._get_element_text(Main.results.result_id)
   
        assert id_pending == id_result, 'The ID of the request is not found in the result table'
        print('Your request automatically rejected')
   
    except TimeoutException:
        self._click(Main.pending_locates.button_reject)
        sleep(1)
        id_result = self._get_element_text(Main.results.result_id)
   
        assert id_pending == id_result, 'The ID of the request is not found in the result table'
        print('Your request manually Rejected')
    return self
   

I want to implement it in a way similar to this, but I have little experience. If anyone can help I will explain in more detail