Link a js on a PHP

Question

Hi I'm a Amateur programer and I need help for my web's programer subject. I'm trying to link this js but on the page show me this on the top Warning: file_get_contents(script404.js): Failed to open stream: No such file or directory in C:\xampp\apps\wordpress\htdocs\wp-content\themes\villanueva-s_theme-brown_nights-\404.php on line 58

<?php
   $script = file_get_contents('script404.js');
   echo "<script>".$script."</script>";
?>

`script404.js` is in the same folder as the php that calls it? And why not just `?>...` — mplungjan, Feb 02 '21 at 11:43
Well the error should be self-explanatory, the file is not located in the path the error message mentions. One question here though would be, why you want to read the file contents via PHP in the first place here, instead of letting the client request the script via URL, by using `` …? — misorude, Feb 02 '21 at 11:46
The error obviously says that the file does not exist in that directory. — Example person, Feb 02 '21 at 11:47

Example person · Answer 1 · 2021-02-02T11:56:08.693

0

You can just use:

echo "<script src=\"script404.js\"></script>";

Or, you should point to the right directory, like:

   $script = file_get_contents('C:/path/to/script404.js');
   echo "<script>".$script."</script>";

Or, I wouldn't advice you to do this, but if it is in the same directory:

   $script = file_get_contents('./script404.js');
   echo "<script>".$script."</script>";

edited Feb 02 '21 at 11:56

answered Feb 02 '21 at 11:43

Example person

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score 0 · Answer 2 · answered Feb 02 '21 at 11:54

0

You must have an invalid path.

You could use __DIR__.'/script404.js' if this file is in the same folder as script you running.

See Evert's answer in Why include __DIR__ in the require_once?

answered Feb 02 '21 at 11:54

LordF

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Link a js on a PHP

2 Answers2