Python permutations with repetitions

Question

If I use "itertools.permutations", I don't get all possible combinations. (i.e. "abb" or "cbc")

import itertools
charList = ["a", "b", "c"]

per = itertools.permutations(charList, 3)

for val in per:
    print(val)

I'm searching for something like "itertools.product", but it works only for numbers.

*I'm searching for something like "itertools.product", but it works only for numbers.* - that's simply not true... — Tomerikoo, Feb 03 '21 at 14:43
@Tomerikoo Can you help me, for my situation it is not working. — Paski7, Feb 03 '21 at 14:46
So [edit] the question with a [mre]. Part of that is what you tried, what you got, and how is that different from what you expect — Tomerikoo, Feb 03 '21 at 14:49
If you want strings instead of tuples of characters, you'll need `list(map(''.join, product(charList, repeat=3)))` instead. — chepner, Feb 03 '21 at 14:51
Does this answer your question? [Generating permutations with repetitions](https://stackoverflow.com/questions/3099987/generating-permutations-with-repetitions) — Tomerikoo, Feb 03 '21 at 14:53

score 1 · Accepted Answer · answered Feb 03 '21 at 14:54

import itertools
x = ['a', 'b', 'c']
print([''.join(p) for p in itertools.product(x, repeat=3)])

Will produce:

['aaa', 'aab', 'aac', 'aba', 'abb', 'abc', 'aca', 'acb', 'acc', 'baa', 'bab', 'bac', 'bba', 'bbb', 'bbc', 'bca', 'bcb', 'bcc', 'caa', 'cab', 'cac', 'cba', 'cbb', 'cbc', 'cca', 'ccb', 'ccc']

Python permutations with repetitions

1 Answers1