jQuery checking for spurious entry

Question

I have a form which the user has to fill in. A couple of fields are required to have a minimum of 50 characters. I need to stop the user from entering i.e. over 50 full stops, or another letter/number. I've managed to trap the entry of multiple full stops but does anyone know of a JavaScript/jQuery regular expression to find maybe 5 or more of any character in sequence?

Many thanks in advance,

Jason

Possible duplicate: http://stackoverflow.com/questions/3779477/regex-for-detecting-the-same-character-more-than-five-times — kei, Jul 06 '11 at 22:28
@kei thanks that's great for PHP, but I need to regex it client side using Javascript. How would I go about using this expression with Javascript? — superjaz1, Jul 06 '11 at 22:46
Thanks for the pointer, I managed to figure it out :) `code` myvar.match(/(\S){5,}/g) `code` — superjaz1, Jul 07 '11 at 00:44
@superjaz1, sorry, haven't noticed that you already solved your problem. Please post your answer and mark it as accepted even if you managed to find it by yourself. — Hnatt, Jul 20 '11 at 13:06
@Hnatt I tried when I found the solution but it wouldn't let me. First time here sorry. I'll try again — superjaz1, Jul 22 '11 at 20:39
@Hnatt thanks! I've accepted your answer, yours seems to work better anyway :) — superjaz1, Jul 23 '11 at 20:01

score 0 · Accepted Answer · answered Jul 20 '11 at 13:02

0

Try this:

str.match(/(.)\1{5,}/);

This means: match any character, place it in a capturing group 1, and match this group repeating 5 or more times.

answered Jul 20 '11 at 13:02

Hnatt

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jQuery checking for spurious entry

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