It looks like you're trying to get the next day as a string. Your best bet is to let the Date
object do the rollover between months and years for you, like this:
getFutureDateTime: function () {
var dt = new Date();
dt.setDate(dt.getDate() + 1); // Will handle rollover for you
var year = dt.getFullYear();
var month = dt.getMonth() + 1;
var day = dt.getDate();
var hour = dt.getHours();
var minute = dt.getMinutes();
var second = dt.getSeconds();
if (month.toString().length == 1) {
month = '0' + month;
}
if (day.toString().length == 1) {
day = '0' + day;
}
if (hour.toString().length == 1) {
hour = '0' + hour;
}
if (minute.toString().length == 1) {
minute = '0' + minute;
}
if (second.toString().length == 1) {
second = '0' + second;
}
var dateTime = year + '/' + month + '/' + day + ' ' + hour + ':' + minute + ':' + second;
return dateTime;
},
Note that if you're doing this in any vaguely modern environment, you can use padStart
on the string (and padStart
is easily polyfilled):
getFutureDateTime: function () {
var dt = new Date();
dt.setDate(dt.getDate() + 1); // Will handle rollover for you
var dateTime =
year.toString().padStart(2, "0") +
"/" +
month.toString().padStart(2, "0") +
"/" +
day.toString().padStart(2, "0") +
" " +
hour.toString().padStart(2, "0") +
":" +
minute.toString().padStart(2, "0") +
":" +
second.toString().padStart(2, "0");
return dateTime;
},
You could give yourself a utility function for the padding, to avoid repeating yourself:
function padZero2(val) {
return String(val).padStart(2, "0");
}
// ...
getFutureDateTime: function () {
var dt = new Date();
dt.setDate(dt.getDate() + 1); // Will handle rollover for you
var dateTime =
padZero2(year) +
"/" +
padZero2(month) +
"/" +
padZero2(day) +
" " +
padZero2(hour) +
":" +
padZero2(minute) +
":" +
padZero2(second);
return dateTime;
},
Similarly, if you use an ES2015 template literal, it may be a bit clearer:
getFutureDateTime: function () {
const dt = new Date();
dt.setDate(dt.getDate() + 1); // Will handle rollover for you
const dateTime = `${padZero2(year)}/${padZero2(month)}/${padZero2(day)} ${padZero2(hour)}:${padZero2(minute)}:${padZero2(second)}`;
return dateTime;
},