arguments starting with 0 giving different numbers than intended in JavaScript?

Question

when I try to get arguments starting with 0, like this case here 012 it is transferring it to 010 why is that can someone explain?

function func1(a, b, c) {
  console.log(arguments[0]);

  console.log(arguments[1]);
  
  console.log(arguments[2]);
}

func1(1, 012, 3);

How is your expected output "2" on second index, when you pass "012"? — GetSet, Feb 05 '21 at 18:03
Images are not code. Show code. You can even write it so it runs here. Use the tools provided please. — GetSet, Feb 05 '21 at 18:05
There is a good amount of information around this [here](https://stackoverflow.com/questions/35047982/javascript-0-in-beginning-of-number). — Luke Brobbs, Feb 05 '21 at 18:06
In Javascript a number starting with 0 is interpreted as octal. — A Haworth, Feb 05 '21 at 18:12

score 0 · Answer 1 · answered Feb 05 '21 at 18:11

0

In JS the leading 0 converts the given number in octal base so 012 = (12)8 = (10)10

answered Feb 05 '21 at 18:11

DDomen

score 0 · Answer 2 · answered Feb 05 '21 at 18:14

0

In Javascript a number starting with 0 is interpreted as octal.

BUT the console log is showing it to you in decimal.

012 = 1*8 + 2 in decimal which is 10.

answered Feb 05 '21 at 18:14

A Haworth

2 Answers2